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	<title>Comments for Umair&#039;s Blog</title>
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	<link>http://umairsaeed.com</link>
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	<lastBuildDate>Fri, 04 May 2012 12:35:32 +0000</lastBuildDate>
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	<item>
		<title>Comment on Snapshots in Xcode by Ashvin</title>
		<link>http://umairsaeed.com/2011/01/12/snapshots-in-xcode/#comment-225</link>
		<dc:creator><![CDATA[Ashvin]]></dc:creator>
		<pubDate>Fri, 04 May 2012 12:35:32 +0000</pubDate>
		<guid isPermaLink="false">https://umairsd.wordpress.com/?p=141#comment-225</guid>
		<description><![CDATA[Thanx..]]></description>
		<content:encoded><![CDATA[<p>Thanx..</p>
]]></content:encoded>
	</item>
	<item>
		<title>Comment on Dependency Properties in Silverlight by sushil</title>
		<link>http://umairsaeed.com/2010/04/16/dependency-properties/#comment-220</link>
		<dc:creator><![CDATA[sushil]]></dc:creator>
		<pubDate>Tue, 24 Apr 2012 17:01:15 +0000</pubDate>
		<guid isPermaLink="false">http://umairsd.wordpress.com/2010/04/16/dependency-properties/#comment-220</guid>
		<description><![CDATA[Very much helpful !! Thanx!! :)]]></description>
		<content:encoded><![CDATA[<p>Very much helpful !! Thanx!! <img src='http://s0.wp.com/wp-includes/images/smilies/icon_smile.gif' alt=':)' class='wp-smiley' /> </p>
]]></content:encoded>
	</item>
	<item>
		<title>Comment on Creating a Custom XAML TypeConverter by JvanLangen</title>
		<link>http://umairsaeed.com/2010/02/03/creating-a-custom-xaml-typeconverter/#comment-219</link>
		<dc:creator><![CDATA[JvanLangen]]></dc:creator>
		<pubDate>Thu, 19 Apr 2012 12:13:23 +0000</pubDate>
		<guid isPermaLink="false">http://umairsd.wordpress.com/2010/02/03/creating-a-custom-xaml-typeconverter/#comment-219</guid>
		<description><![CDATA[Hi, nice article, but i think you shouldn&#039;t misuse the try/catch


		public Double InternalParseInput(String inputString)
		{
			Double doubleValue;

			if (Double.TryParse(inputString, out doubleValue))
				return doubleValue;
			else
				return default(Double);
		}]]></description>
		<content:encoded><![CDATA[<p>Hi, nice article, but i think you shouldn&#8217;t misuse the try/catch</p>
<p>		public Double InternalParseInput(String inputString)<br />
		{<br />
			Double doubleValue;</p>
<p>			if (Double.TryParse(inputString, out doubleValue))<br />
				return doubleValue;<br />
			else<br />
				return default(Double);<br />
		}</p>
]]></content:encoded>
	</item>
	<item>
		<title>Comment on Stern-Brocot Tree by Umair</title>
		<link>http://umairsaeed.com/2011/01/27/stern-brocot-tree/#comment-210</link>
		<dc:creator><![CDATA[Umair]]></dc:creator>
		<pubDate>Thu, 12 Apr 2012 07:06:07 +0000</pubDate>
		<guid isPermaLink="false">https://umairsd.wordpress.com/?p=151#comment-210</guid>
		<description><![CDATA[Ah, good catch. Thank you. I&#039;ve fixed it now.]]></description>
		<content:encoded><![CDATA[<p>Ah, good catch. Thank you. I&#8217;ve fixed it now.</p>
]]></content:encoded>
	</item>
	<item>
		<title>Comment on Stern-Brocot Tree by pedant</title>
		<link>http://umairsaeed.com/2011/01/27/stern-brocot-tree/#comment-207</link>
		<dc:creator><![CDATA[pedant]]></dc:creator>
		<pubDate>Mon, 02 Apr 2012 21:45:58 +0000</pubDate>
		<guid isPermaLink="false">https://umairsd.wordpress.com/?p=151#comment-207</guid>
		<description><![CDATA[Else q=M, terminate search.
typo?

&quot;k=M&quot;?]]></description>
		<content:encoded><![CDATA[<p>Else q=M, terminate search.<br />
typo?</p>
<p>&#8220;k=M&#8221;?</p>
]]></content:encoded>
	</item>
	<item>
		<title>Comment on Finding the Start of a Loop in a Circular Linked List by Amit</title>
		<link>http://umairsaeed.com/2011/06/23/finding-the-start-of-a-loop-in-a-circular-linked-list/#comment-194</link>
		<dc:creator><![CDATA[Amit]]></dc:creator>
		<pubDate>Sun, 18 Mar 2012 16:06:01 +0000</pubDate>
		<guid isPermaLink="false">https://umairsd.wordpress.com/?p=186#comment-194</guid>
		<description><![CDATA[Coolest explanation ever!!!!! Highly useful.]]></description>
		<content:encoded><![CDATA[<p>Coolest explanation ever!!!!! Highly useful.</p>
]]></content:encoded>
	</item>
	<item>
		<title>Comment on Finding the Start of a Loop in a Circular Linked List by Umair</title>
		<link>http://umairsaeed.com/2011/06/23/finding-the-start-of-a-loop-in-a-circular-linked-list/#comment-179</link>
		<dc:creator><![CDATA[Umair]]></dc:creator>
		<pubDate>Thu, 08 Mar 2012 12:30:37 +0000</pubDate>
		<guid isPermaLink="false">https://umairsd.wordpress.com/?p=186#comment-179</guid>
		<description><![CDATA[Actually, for your example: For the first pass, both the fast and the slow pointers will meet at D to detect the presence of the loop. Here&#039;s the path that they&#039;ll follow:

Slow: A -&gt; B -&gt; C -&gt; D
Fast: A -&gt; C -&gt; E -&gt; D

Now, when you reset the slow pointer to the beginning, and move them one node at a time, they&#039;ll follow the patterns as below:

Slow: A -&gt; B -&gt; C
Fast: D -&gt; E -&gt; C]]></description>
		<content:encoded><![CDATA[<p>Actually, for your example: For the first pass, both the fast and the slow pointers will meet at D to detect the presence of the loop. Here&#8217;s the path that they&#8217;ll follow:</p>
<p>Slow: A -&gt; B -&gt; C -&gt; D<br />
Fast: A -&gt; C -&gt; E -&gt; D</p>
<p>Now, when you reset the slow pointer to the beginning, and move them one node at a time, they&#8217;ll follow the patterns as below:</p>
<p>Slow: A -&gt; B -&gt; C<br />
Fast: D -&gt; E -&gt; C</p>
]]></content:encoded>
	</item>
	<item>
		<title>Comment on Finding the Start of a Loop in a Circular Linked List by anshul</title>
		<link>http://umairsaeed.com/2011/06/23/finding-the-start-of-a-loop-in-a-circular-linked-list/#comment-169</link>
		<dc:creator><![CDATA[anshul]]></dc:creator>
		<pubDate>Sat, 03 Mar 2012 21:10:20 +0000</pubDate>
		<guid isPermaLink="false">https://umairsd.wordpress.com/?p=186#comment-169</guid>
		<description><![CDATA[Are you sure this works for all cases?
Assume the case that you started out with namely:
A -&gt; B -&gt; C -&gt; D -&gt; E -&gt; C
When you increment the slow pointer by one and the fast pointer with two, they will eventually meet at E (n and 2n as you later describe).
Now if you set the slow pointer to A and let the fast pointer be and start incrementing them one node at a time they will follow the pattern as below:
Slow:  A -&gt; B -&gt; C -&gt; D -&gt; E
Fast:  E -&gt; C -&gt; D -&gt; E -&gt; C


Please correct me if I got anything wrong.]]></description>
		<content:encoded><![CDATA[<p>Are you sure this works for all cases?<br />
Assume the case that you started out with namely:<br />
A -&gt; B -&gt; C -&gt; D -&gt; E -&gt; C<br />
When you increment the slow pointer by one and the fast pointer with two, they will eventually meet at E (n and 2n as you later describe).<br />
Now if you set the slow pointer to A and let the fast pointer be and start incrementing them one node at a time they will follow the pattern as below:<br />
Slow:  A -&gt; B -&gt; C -&gt; D -&gt; E<br />
Fast:  E -&gt; C -&gt; D -&gt; E -&gt; C</p>
<p>Please correct me if I got anything wrong.</p>
]]></content:encoded>
	</item>
	<item>
		<title>Comment on Creating a Custom XAML TypeConverter by Sumit</title>
		<link>http://umairsaeed.com/2010/02/03/creating-a-custom-xaml-typeconverter/#comment-142</link>
		<dc:creator><![CDATA[Sumit]]></dc:creator>
		<pubDate>Fri, 20 Jan 2012 11:56:34 +0000</pubDate>
		<guid isPermaLink="false">http://umairsd.wordpress.com/2010/02/03/creating-a-custom-xaml-typeconverter/#comment-142</guid>
		<description><![CDATA[Really a nice article. Thanks.]]></description>
		<content:encoded><![CDATA[<p>Really a nice article. Thanks.</p>
]]></content:encoded>
	</item>
	<item>
		<title>Comment on Finding the Start of a Loop in a Circular Linked List by Sreeram</title>
		<link>http://umairsaeed.com/2011/06/23/finding-the-start-of-a-loop-in-a-circular-linked-list/#comment-129</link>
		<dc:creator><![CDATA[Sreeram]]></dc:creator>
		<pubDate>Sun, 01 Jan 2012 18:23:36 +0000</pubDate>
		<guid isPermaLink="false">https://umairsd.wordpress.com/?p=186#comment-129</guid>
		<description><![CDATA[Awesome job man.. 
Clearly explained.. 
Thank you buddy..!]]></description>
		<content:encoded><![CDATA[<p>Awesome job man..<br />
Clearly explained..<br />
Thank you buddy..!</p>
]]></content:encoded>
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